Theoretical Population Biology 12S (2019) 38-55
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Theoretical Population Biology
ITSEVIER journal home pa go: ..vww.elscvier.comflocateApb
A two-player iterated survival game
John Wakeley a.*, Martin Nowak a'b'c
'Department of Organismic and Evolutionary Biology. Harvard University. Cambridge. MA, 02138. USA
b Program for Evolutionary Dynamics. Harvard University. Cambridge. MA 02138. USA
' Department of Mathematics, Harvard University. Cambridge, hfA 02138, USA
ARTICLE INFO ABSTRACT
Ankle history: We describe an iterated game between two players, in which the payoff is to survive a number of steps.
Received 22 May 2018 Expected payoffs are probabilities of survival. A key feature of the game is that individuals have to survive
Available online 12 December 2018 on their own if their partner dies. We consider individuals with hardwired, unconditional behaviors
Keywords: or strategies. When both players are present. each step is a symmetric two-player game. The overall
Prisoner's Dilemma survival of the two individuals forms a Markov chain. As the number of iterations tends to infinity, all
Survival game probabilities of survival decrease to Zero. We obtain general, analytical results for n-step payoffs and use
Iterated game these to describe how the game changes as it increases. In order to predict changes in the frequency of
Replicator equation a cooperative strategy over time, we embed the survival game in three different models of a large, well-
Moran model mixed population. Two of these models are deterministic and one is stochastic. Offspring receive their
parent's type without modification and (finesses are determined by the game. Increasing the number
of iterations changes the prospects for cooperation. All models become neutral in the limit (ri co).
Further, if pairs of cooperative individuals survive together with high probability, specifically higher than
for any other pair and for either type when it is alone, then cooperation becomes favored if the number
of iterations is large enough. This holds regardless of the structure of pairwise interactions in a single
step. Even if the single-step interaction is a Prisoner's Dilemma, the cooperative type becomes favored.
Enhanced survival is crucial in these iterated evolutionary games: if players in pairs start the game with
a fitness deficit relative to lone individuals, the prospects for cooperation can become even worse than in
the case of a single-step game.
02018 Elsevier Inc. All rights reserved.
I. Introduction the temptation, to be the one who comes out ahead even if it is at
the expense of other individuals.
More than a century ago, Kropotkin (1902) argued that what Indeed, game theory and evolutionary theory have uncovered
he called mutual aid should be ranked among the main factors of numerous situations in which cooperative or otherwise helping
evolution. aneven more important driver ofevolution than within- behaviors are detrimental t0 the individual or selectively disad-
species competition. The idea ofmutual aid is similar to that ofmu- vantageous (Hofbauer and Sigmund, 1998; Mesterton-Gibbons.
tualism: partnerships may be beneficial to both partners and thus 2000; Cressman, 2005; Schecter and Gintis, 2016). It has been
unconditionally favored. Kropotkin had been deeply impressed shown using a variety of models that such behaviors can be disfa-
by the abilities of animals to endure harsh winters and perilous vored even if there are obvious advantages to mutual cooperation.
migrations in northern Eurasia by living together and supporting For example, in the classic two-player game called the Prisoner's
each other in situations where a lone animal had little chance Dilemma (Tucker, 1950; Rapoport and Chammah, 1965; Axelrod.
1984). cooperation results in a "reward payoff' if one's partner
of surviving. Thus, he inferred a connection between cooperative
behaviors and survival under adverse conditions. But Kropotkin did also cooperates but a "suckers payoff' if one's partner defects.
Defection yields a "temptation payoff" if one's partner cooperates
not spell out the ways in which adversity might favor cooperative
but a "punishment payoff" if one's partner also defects. The reward
behaviors, nor did he consider that cooperative behaviors could be
is of course better than the punishment, but it is further assumed
disadvantageous. He took the very fact that animals seem to do
that the temptation payoff is greater than the reward, and the
better in groups than alone as evidence for mutual aid, apparently sucker's payoff is even worse than the punishment This leads to a
unaware that any interaction presents the opportunity, or at least paradox: an individual who defects always receives a higher payoff
but it is clearly illogical for everyone to defect.
* Corresponding author. The Prisoner's Dilemma, in which the payoff for defection is
E-mail address: wakeleyefas.harvard.edu U. Wakeley). higher than for cooperation regardless of one's partner behavior,
hups://doLorg/10.1016b.tpb.2018.12.001
0040-S809/0 2018 Elsevier Inc. All rights reserved.
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J. Wakeley and M. Nowak/Theoretical Population Biology 125(2019)38-55 39
Table 1 we will call PD for short.Ifa(n) > c(n)and b(n) a d(n), cooperation
The payoff, a(n). J(n), c(n) or d(n). that an individual receives in a symmetric has the higher payoff only when one's partner cooperates. This is
two-player game depends both on the individual and on the individual's paltrier.
In a survival game, these payoffs are probabilities of survival A and B denote
the Stag-Hunt class of games, or SH for short. If a(n) e c(n) and
two possible strategies or types of individuals (e.g. Dove and Hawk). Payoffs are b(n) > d(n), cooperation has the higher payoff only when one's
simultaneously awarded to both players, i.e. each is considered the Individual (and partner does not cooperate. This is the Hawk-Dove class, or HD for
the other the Partner) and awards a payoff according to the table. short. Finally, if a(n) > c(n) and b(n) > d(n), cooperation has the
Partner higher payoff regardless of the partner. We follow De Jaegher and
A Hoyer (2016) and call this a Harmony Game. or HG for short.
A o(n) b(n) We refer to the n-step survival game as a repeated or iterated
Individual
B c(n) d(n) game because the payoff structure in each of then steps is identical
and equivalent to the single-step version of the game. The notion
of repeated or iterated games is generally predicated on the idea
that individuals can act differently in different steps and can react
represents one of four possible types of two-player games. It is
the polar opposite of what Kropotkin (1902) imagined for mutual to their partner's behavior. When this is true, the relatively sim-
aid, that instead it would cooperation that would always yield ple conclusions about which strategy may be favorable based on
the higher payoff. Between these extremes lie two other kinds of Table 1 do not necessarily hold. For example, if two individuals
games. In the Stag Hunt (Skyrms, 2004) and related games, the play an iterated Prisoner's Dilemma under these conditions, then
payoff to an individual is higher ifit matches the partner's behavior reactive strategies like Tit-for-Tat (Axelrod, 1984) or win-stay,
regardless of what that behavior is. Cooperators in the Stag Hunt lose-shift (Nowak and Sigmund, 1993) can be favored over the
go for the big game, a stag, which two such individuals can catch single-iteration strategy of always-defect. Such repeated games
but one alone cannot. Non-cooperators opt out of the big-game allow for the phenomena ofdirect and indirect reciprocity (Trivers.
hunt and accept a middling payoff, a hare, which a single individual 1971; Nowak and Sigmund, 1998) and trigger strategies which
can catch. In this case, cooperation yields the higher payoff only punish non-cooperation (Osborne and Rubinstein, 1994). These
when one's partner also cooperates. The Hawk-Dove game (May- are examples of a general phenomenon of behavioral responsive-
nard Smith and Price, 1973; Maynard Smith, 1978) represents the ness (Van Cleve and Alccay, 2014) which is one of a small number
fourth kind, in which havinga different behavior than one's partner of mechanisms known to promote the evolution of costly cooper-
produces a higher payoff. Doves cooperate by sharing resources but ation (reviewed in Nowak, 20066; Van Cleve and Alccay, 2014).
retreat when challenged. Hawks do not cooperate. They are ready We do not consider reactive strategies or behavioral respon-
to fight to avoid leaving an interaction empty-handed. A Hawk gets siveness in this work. Individuals have one of two possible simple
the entire resource when facing a Dove but suffers badly when fac- strategies: A or B as in Table 1. When both individuals are present,
ing another Hawk Hawk and Dove, ofcourse, refer to stereotypical which is always the case initially, their survival probabilities in
personalities not animals. In this last case, cooperation yields the each iteration are given by the single-step version of Table 1. i.e.
higher payoff only when one's partner does not cooperate. Besides with a( 1), b(1), c(1) and d( 1). We will refer to these single-step
Hawk-Dove, other well-studied games of this type are the game survival probabilities as a, b, c and d. The n-step survival proba-
of chicken and the snowdrift game (Doebeli and liauert. 2005: bilities, a(n), b(n), c(n) and d(n), will depend on these as well as on
Nowak, 2006a). the probabilities of survival when an individual is alone. Although
We introduce a two-player survival game which can fall into the game always begins with two individuals, if one dies the other
any of these four classes. It may also change, for example from a must continue. In the remaining steps, a loner plays a game against
Hawk-Dove game into a Prisoner's Dilemma, depending on one Nature. Specifically, a loner survives a single step with probability
key feature, the length of the game. In this game, an initially as if it has strategy A and probability do if it has strategy B. We are
sampled pair of individuals confronts a hazardous situation which especially interested in cases in which the single-step, two-player
is repeated n times. With reference to Kropotkin (1902). we might game defined by a, b. c and d is of a different type than the n-step
imagine that each day of a long journey presents a similar set of game defined by a(n), b(n), c(n) and d(n).
challenges which threaten survival. They might, for example, be Several previous works have considered games in which the
trying to survive a number of very cold nights or attempting to random survival of individuals is an important factor and envi-
defend themselves repeatedly against a predator. How they fare in ronmental conditions may be harsh. Eshel and Weinshall (1988)
each step depends on their behavior and their partner's behavior. introduced a model in which payoffs are probabilities of survival.
The payoff for an individual is all or nothing: either survive to Payoffs were drawn randomly from a distribution, and the game
the end of the game or not. Crucially, an individual must face the was repeated with a fixed probability. As in the model we pro-
perilous situation alone for the remainder of the game ifits partner pose, Eshel and Weinshall (1988) allowed that the game may con-
dies. Survival payoffs are thus meted out at each step, and this will tinue even if one individual dies. They considered optimal strategy
be important for determining total payoffs in the game. Denoting choice by individuals under the assumption that individuals have
survival as I and death as 0, the expected total payoff to an perfect knowledge of the game's structure, including the distribu-
individual in a given situation(i.e. witha specified partner initially) tion of the payoffs. Eshel and Shaked (2001)described a similar sur-
is its probability of surviving to the end of the game. The n-step vivaI game but included a general probability that both members
survival game is a symmetric two-player game with total payoffs, of a pair survive, thus allowing for arbitrary synergistic effects of
a(n), d(n), c(n) and d(n) as Table 1. Using Table 1 to represent an partnership (Hauert et al.. 2006; Kun et al.. 2006) within each step
n-step game that is a Prisoner's Dilemma, with A for cooperation of the game. Eshel and Weinshall (1988) had assumed that pairwise
and B for defection, the reward would be a(n), the sucker's payoff survival probabilities were the products of two individual survival
b(n), the temptation payoff c(n) and the punishment d(n). probabilities.
More generally, depending on a(n), b(n), c(n) and d(n), any Garay (2009) combined the idea of a survival game with the
n-step survival game falls into one of the four classes described "selfish herd" theory of Hamilton (1971) to produce a model of
above. Ignoring the detail that some payoffs might be identical, cooperation between pairs of individuals in defense against re-
these are defined as follows.Ifa(n) < c(n) and b(n) < d(n). cooper- peated attacks by a predator. Individuals were of two possible
ation has the lower payoff regardless of the partner. Then the game types, characterized by a probability of helping their partner in
falls into the class exemplified by the Prisoner's Dilemma. which defense against attack. Garay (2009) derived the total survival
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40 J. Wakefey and M. Nowak/ Theoretical Population Biology 125 (2019)38-55
probabilities of individuals in different kinds of partnerships given lower payoff given partners of type A and B, respectively. In game
a faced number ofattacks, and used these to describe evolutionarily theory and much of evolutionary game theory which treats pop-
stable strategies (Maynard Smith and Price, 1973) in an infinite ulations, these two comparisons are relevant because individuals
population. Using the example contrast of one attack versus eight choose or modify their strategies based on their knowledge of
attacks, this revealed cases in which helping could not invade a the game and its outcomes (Sandholm, 2010). When individuals
completely selfish population given a one-attack game but could cannot alter or choose their behaviors but payoffs affect fitness.
invade if the number of attacks was larger (Garay. 2009). the same sorts of evolutionary models are used to predict changes
Kropotkin's notion that high levels of adversity could favor in the frequency of hardwired behaviors in a population. In this
cooperation has also been studied using simulations of structured section, we briefly summarize the evolutionary game dynamics of
populations. Harms (2001) found that in a Prisoner's Dilemma co- infinite populations.
operators could gain an advantage at the inhospitable margins of a The replicator equation, in which general payoffs are inter-
population by colonizing patches cleared by the local extinction of preted as contributions to individual fitness (Taylor and Jonker,
defectors. More recent simulations of another model by Smaldino 1978; Hofbauer et al., 1979; Zeeman, 1980; Schuster and Sigmund,
et al. (2013) also found cases in which cooperation can be favored 1983; Hofbauer and Sigmund, 1988, 1998) provides an evolution-
despite the Prisoner's Dilemma. Specifically, if there is a high cost ary setting for the classification of two-player games. In a survival
of living for all individuals which, if unchecked, would lead to the game payoffs are fitnesses, specifically viabilities.If x is the relative
extinction of the population and if occasional interactions with frequency of A in an infinite population, the replicator equation
cooperators are required for survival, then cooperation can be gives the instantaneous rate of change
favored. As in Harms (2001). the success ofcooperators in this case
relied on their ability to form clusters (Smaldino et al., 2013). = — x)(la(n)— c(n)Ix lb(n)— d(n)j(1 — x)). (1)
De Jaegher and Hoyer (2016) considered two game-theoretic Eq. (I) illustrates the evolutionary consequences of partner-
models of the behavior and ecology of a pair of individuals, in dependent payoffs when pain are formed at random in proportion
which higher levels of adversity can change the type of the game. to the frequencies ofA and B. When x x 1. so thatA is very common
Their Model I includes a degree ofcomplementarity which rescales and nearly all partners are A, it is the sign of a(n) — c(n) that
payoffs for mixed-strategy pairs compared to same-strategy pain. determines whether A is favored in the population. On the other
and which could represent an environmental challenge for mixed hand, when x x 0, so that nearly all partners are B, the sign of
pairs. Their Model 2 includes a number of attacks by a predator b(n) — d(n) is what matters. Beyond this. Eq. ( I ) shows that for any
on individuals protecting a common resource. Cooperators are value of x, it is the sign of (a(n) — c(n)ix lb(n) — d(n)1(1 — x)
immune to attacks while defectors can sustain at most one at- that determines whether A is favored. Thus. in a population and in
tack before the common resource is lost. As in Garay (2009). the evolution the relative magnitudesof both a(n)—c(n) and b(n)—d(n)
number of attacks indicates the level of environmental challenge. are important. such that one may dominate the other at a given
Cooperation may be disfavored when the number of attacks is value of x. This is not something that can be gleaned directly from
small and yet become favored when the number of attacks is large. Table 1.
Depending on the other parameters in the model, however, a range Without mutation, the fates ofA and B in this infinite population
ofother switches between types of games may occur as the number are entirely determined by Eq. (1). From any starting point, x will
of attacks increases. De Jaegher (2017) extended these results to move deterministically toward one of three possible equilibria
multi-player games. which are the solutions of k = 0 and which may correspond to
Our concerns here are similar to those of Garay (2009) and the evolutionarily stable strategies mentioned in Section 1. Two
De Jaegher and Hoyer (2016). We study how the structure of the monomorphic equilibria always exist. z = 0 and 1 = 1. The
two-player iterated survival game changes as a function of its polymorphic equilibrium
parameters, in particular the number of steps it. We compare the
conclusions for single-step games with those for n-step games. — b(n) — d(n) (2)
Because the payoffs which are probabilities ofsurvival in this game b(n) — d(n) — a(n) c(n)
decrease as n increases. n is a measure of adversity. We present might also exist, depending on the payoffs.It exists, which is to say
general results for any level ofadversity, then focus on the possible that Eq. (2) gives a biologically meaningful value, when a(n), b(n),
structures of large-n games. We find conditions under which any c(n) and d(n) are such that 0 < it < 1.
type of single-step game, be it a Prisoner's Dilemma, a Stag Hunt or Eq. ( I ) defines the same four types of symmetric two-player
a Hawk-Dove game. will become a Harmony Game as n increases. games. In the PD case, a(n) — c(n) < 0 and b(n) — d(n) < 0.
We identify three other large-n results, one of which shows the and Eq. (1) shows that z < 0 for all values of x E (0, 1). Starting
opposite: single-step advantages of cooperation may disappear at any value x < 1, the frequency of A will decrease to zero. The
as n grows. To facilitate comparisons, we define A throughout as polymorphic equilibrium given by Eq. (2) does not exist. In the SH
the more cooperative type based on the single-step game, so that case, a(n)—c(n) > 0 and b(n)—d(n) < O. ThenA isdisfavored when
a > d. Thus, AA pairs survive better than BB pairs. We consider x is below the polymorphic equilibrium Si in Eq. (2) and favored
both infinite and finite populations but in neither case is there when x > 2. The polymorphic equilibrium exists and is unstable.
spatial or any other kind of structure. We do not develop a detailed In the HD case, a(n) — c(n) < 0 and b(n) — d(n) > 0. Then A is
biological. ecological or behavioral model. Akin to what is done in favored when x <2. and disfavored when x > z. The polymorphic
models of diploid viability selection, we describe the game and its equilibrium exists and is stable. In the HG case. a(n)— c(n) > 0 and
results directly in terms of survival probabilities. Our results are b(n) — d(n) > O. Then k > 0 and A is favored for all x e (0. 1). The
applicable to a wide range of specific scenarios in which payoffs polymorphic equilibrium does not exist. Fig. I shows examples of a
affect viability (as opposed to fertility or fecundity) and in which Prisoner's Dilemma, a Stag Hunt and a Hawk-Dove survival game.
partnerships may either enhance survival or detract from it. depicting payoffs in their contexts (upper panels) and associated
shapes of k (lower panels). A Harmony Game is not shown but
It Evolutionary dynamics would be another case of directional selection, like Fig. ID but with
1 > 0 for all x e (0, 1).
Comparing a(n) to c(n) and b(n) to d(n) in Table I indicates These four types of games defined by the shape of ic over the
whether the more cooperative strategy A yields the higher or the interval 10, 1] are identical to what is observed in classical models
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J. Wakeley and M. Nowak/Theoretical Population Biology 125(2019)38-55 41
A
1.
Prisoners Dilemma
c(n)
B
1.
Stag Hunt C
1. Hawk-Dove
cm)
1 098
096 a(n) a(n)
=
a
7
o sa
ow
n)
n)
k 0.98
0.98
..................., v'z U^) a(n)
0.94 E
-0 094 :E 0.94
2 M^> c • n) d(n)
BB M BA Ark - BB MBA AA BB MBA AA
Individual-Partner Pair Individual-Partner Pair Individual-Paitner Pair
D E Stag Hunt F Hawk-Dove
o.
0.001 0.
-0.CO1 0.
X -0.002 A -0.001 A -0.001
-0.003 -0.002
-0.003 -0.002
0 0.25 0.5 0.75 0 0.25 0.5 0.75 0 0.25 0.5 0.75 1
x x
Flg. 1. A and D: Prisoner's Dilemma with payoffs a = 0.97. b = 0.94, c = 0.99, d = 0.95 (a linear transformation of the classic R = 3, 5 = 0, 7 = 5, P = 1 of Axelrod
0984e.g.a = 0.94 + R/100).B and E: Stag Hunt, with a = 0.99.0 = 0.94, c = d = 0.97 (corresponding to a stag value of0.05 and a hare value of0.03 added to a baseline
survival probability of 0.94). C and F: Hawk-Dove, with a = 0.97, b = 0.95, c = 0.99, d = 0.94 (corresponding to a cost of fighting of 0.03 and a resource value of 0.04,
with a baseline survival probability of 0.95). Line segments in A, B and C connect the survival probabilities for B (left) versus A (right) when each occurs with given type
of partner. The curves in D. E and F show k from Eq. (1). In diploid population genetics. these three cases fora are called directional selection (D), underdominance (E) and
overdominance (F).
of diploid viability selection (e.g. see section 4.2 in Nagylaki, 1992). and the state in which both individuals have died which we denote
The difference is that, barring atypical phenomena such as meiotic 0. It is convenient to represent a single iteration using the matrix
drive (Dunn, 1953; Sandler and Novitsky, 1957) or segregation- AA AB BB A B 0
distortion (Sandler and Hiraizumi, 1960; Hard. 1974), standard
IA a2 0 0 2a(1 - a) O (1 — a)2 1
diploid models always have b(n) = c(n). It is by allowing b(n) #
AB 0 be 0 b(1 — r) r(1 — b) (1 — b)( 1 — c)
c(n) that two-player games introduce the paradox of the Prisoner's BB 0 0 d2 0 2d(1 — d) (1 — d)2
Dilemma, in which c(n) > a(n) and d(n) > b(n) but a(n) > d(n). In A 0 0 0 a0 O 1 — ao (3)
order to have c(n) > a(n) and d(n) > b(n) in a standard diploid B 0 0 0 0 1 — do
do
model it would be necessary to have a(n) e d(n). Accordingly. O 0 0 0 0 O 1
the Prisoner's Dilemma is the most stringent form of a cooperative
dilemma (Doebeli and Hauert, 2005; Hauert et al., 2006; Nowak, with entries equal to the transition probabilities among he six
2012). A cooperative dilemma exists when (i) mutual cooperation states. For example, the transition from state AB to state B means
results in a higher payoff than mutual non-cooperation, so that that the B individual survives and the A individual dies. In a single
a(n) > d(n) when A represents cooperation, but (ii) there is incen- step, this occurs with probability c(1— b). Note that the transitions
tive to be non-cooperative in at least one of three ways: (iia) c(n) > in Eq. (3) include the fates of both individuals but the individuals
a(n), (iib) d(n) > b(n) or (iic) c(n) > b(n) (Nowak, 2012). The are not labeled Individual and Partner as they are in Table I.
The process described by Eq. (3) is depicted in Fig. 2. State
Prisoner's Dilemma includes all three of these incentives. Games O is an absorbing state. There is no possibility of transition be-
with fewer barriers to cooperation, such as the Stag Hunt and the tween the paired states M. AB, and BB. Instead each of these
Hawk-Dove game, represent relaxed cooperative dilemmas. The feeds either straight into state 0, from which there is no escape.
Harmony Game involves no cooperative dilemma and presents no or into one of the loner states. A or B. and from there into 0.
barrier to cooperation. Therefore, transitions from any of the starting, paired states to
absorption in state 0 involve either one or two changes of state.
2. An n-step survival game between two players Further, all of the transitions that cannot occur in a single iteration
(the 0 entries in the matrix) cannot ever occur regardless of the
Our survival game always includes n iterations and begins with number of iterations. Because of this simple structure, the n-step
a pair of individuals. In each step, both might survive or one, transition probabilities can be calculated directly by conditioning
the other or both might die. These same outcomes hold for the on the times these transitions take place, i.e. on their positions
in the sequence of n iterations. It is also possible to compute the
complete game, only the probabilities of surviving will be smaller. n-step transition probabilities using standard techniques for
We consider two unconditional strategies. A and B. When both Markov chains, and this provides a useful framework for decom-
players are present, their individual survival probabilities are given posing the process and describing its behavior when n is large.
by the single-step version of Table I with a(1) • a, b(1) • b, Details of the matrix approach are given in the Appendix. but
c(1) • c and d(1) • d. However, the next iteration must be two key features of it inform our presentation. The first is the fact
faced by whoever has survived so far, until all n iterations are done. of the absorbing state (0) in which both individuals have died. It
Thus, an individual might have to play alone. Then the survival will be reached eventually, meaning in the limit n oo. For large
probabilities become ao forA without a partner and do for B without n the game process will be just the approach to this state. Second,
a partner. In all of what follows. A will be the more cooperative when n is large, the rate of approach to state 0 will be given by the
strategy, meaning that a > d. largest non-unit eigenvalue of the matrix in Eq. (3). Because it is an
The n-step survival game is a stochastic process with six possi- upper triangular matrix, the eigenvalues are simply the entries on
ble states: the paired states AA, AB and BB, the loner states A and B, the diagonal. By convention, we call the largest of these 2. = land
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42 J. Wakefey and M. Nowak/Theoretical Population Biology 12S (2019)38-55
Prob(BB 8) = E 2d(1- (14)
I
0 = (d2n A„ 2d( 1 d)
) d2 (15)
® The only other possibility is that neither individual survives, so we
also have
Prob(AA 0) = 1 —Prob(AA AA) — Prob(AA —* A) (16)
Prob(AB —a. 0) = 1 — Prob(AB AB) —Prob(AB A)
.® Prob(AB B) (17)
0 Prob(BB —* 0) = 1 — Prob(BB —a. BB) — Prob(BB B). (18)
a In the Appendix we show how these probabilities are obtained
using techniques for Markov chains.
Eqs. (8) through (15) make it clear that this paired survival
process is one in which the fortunes of individuals may change.
rv R
0 perhaps drastically depending on the values of ao and do relative
to a, b, c and d. Consider starting state AB. Eq. (12) shows how the
probability of beingin state Bat the end ofn iterations is computed.
0 In words, both individuals survive for some time (i-1 steps), then
A dies, and B survives the rest of time (n - i steps). If A dies, B
trades its individual survival probability ofc. which B enjoys in the
Flg. 2. Flow diagram ofthe stochastic process givenby the matrix of Eq. (3).Arrows
show all possible transitions among the six states (A4. At BB. A. B. 0).States AA, AB, presence and A, fora loner survival probability ofdo. It could be that
BB. A and B are transient. State 0 is absorbing. The process always begins in one of do c c, making B worse off after A dies. In fact, B's fate is closely
the three states on the left, M. AB or BB. After n iterations. it may be in any of the tied with A's because this switch could occur quickly if A's survival
six possible states. probability, b, is small. Of course. while there is a cost to B when
A dies (assuming 4 c c), the death of A in this partnership also
represents a rather direct disadvantage toA.In order to understand
note that this corresponds to the eventual absorption in state 0. In whether A or B will prevail in evolution, it is necessary to account
all, we have for the full dynamics of reproduction in a population, with fitnesses
that are determined by this game. We will take this up in Section 3.
= 1, a2, bc, d2, ao, . (4) In the n-step game, the differences a(n) - c(n) and b(n) — d(n)
give the conditions under which A is favored. The n-step payoffs.
Following the discussion of Table 1 and Eq. ( I), we expect the or survival probabilities, are computed by accounting for the two
fates of A and 8 in this iterated game to depend on the relative ways an individual may survive the game. An individual survives
magnitudes of a versus c and b versus d. Eq. (4) suggests that if both it and its partner survive or if it survives but its partner
their fates will also depend on the relative magnitudes of the dies. The total probabilities of individual survival in each kind of
pair survival probabilities. a2. be and d2. and on the loner survival partnership are
probabilities. ao and 4.and that this dependence may be especially a(n) = Prob(AA AA) + Prob(AA -o A)/2
strong when n is large.
We compute the n-step pair survival probabilities directly as _ a2" a—ao + a(1 — a) (19)
a2 — ao ao — a2
Prob(AA —* AA) = a2" (5) b(n) = Prob(AB AB) + Prob(AB A)
Prob(AB —a. AB) = (bcr (6) b ao b(1 — c)
= (kr +4 (20)
be - ao ao — be
Prob(BB BB) = dm. (7) c(n) = Prob(AB AB) Prob(AB B)
Then, by considering the possibility that one of the individuals c — do c(1 — b)
= (bcr +4 (21)
might die in step 1 < i < ri and the other individual survives to be -d o do — bc
the end of the game, we have d(n) = Prob(BB BB) + Prob(BB B)/2
re 2 d dO d — d)
—d" + 4 (22)
Prob(AA -* A) = E (a2)1-1 2a(1 - a)arl d2 — 4 4 - d2
The transitions AA A and BB B are adjusted by a factor
= 02. 4) 2a(1 — a) of 1/2 because they are equally likely to happen by the death
2 — an of the partner as by the death of the focal individual. Eqs. (19)
through (22) are our general results, namely the n-step survival
Prob(AB -> A) = E(bc)i-1b(1 - c)arl probabilities for individuals of types A and B given each kind of
a-t initial partnership. They are exact for any values of a, b, c, d, ao
and do greater than zero and less than one, and for any number
((kr d°) 1_ c) of iterations n 1. As expected, when n = 1, they reduce to the
It single-step survival probabilities a(1) = a, b( 1) = b, c(1) = c and
Prob(AB B) = DbCr I CO — LOCIrj d(1) = d.
i-t
The two key differences in payoff are then
CO — b) a ao
(ocr - d rf c do a(n) - c(n)- am ao + 4 Go ——a2
a)
a
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J. Waketey and M. Nowak/Theoretical Population Biology 125 (2019)38-55 43
— c(I — b) iterations increases. We present results both for a(n) — c(n) and
_ (krc__ (23)
be —do ° do — bc b(n) — d(n) and in terms of the unified predictions of Eq. ( I ).
bt c) Eq. (1) is a standard replicator equation for a symmetric two-
b(n)— d(n)= (bon + aiot player game. In the Appendix, we show how it may be derived
bc —ao
ao aol — bc
for the n-step survival game. This has two notable features: the
_ d2nd_
do d(1 — d)
(24) game works by removing individuals from the population instead
d2 — do ° do — d2
of affecting their rates of reproduction and the derivation follows
Each term in Eqs. (23) and (24) includes a factor A? for one of the pairs of individuals rather than single individuals. Also in the
non-unit eigenvalues (a2, bc, d2. a0. do). These factors are positive. Appendix, we take a discrete-time, population-genetic approach
The denominator of each term is the difference between two to show that the change in frequency of A over one generation is
eigenvalues.If we know the eigenvalues, we know whether the de-
nominators are positive or negative. In some cases the numerator Ax = x(1 — x)0a(n)— c(n)1x (b(n)— d(n)1(1 — x))/th, (27)
might be negative, but by the definition of a, b, c, d, ao and do as which is identical in form to ic in Eq. ( I ) but scaled by the average
probabilities, the numerator will be positive if the denominator is fitness, tb. Eq. (27) is directly comparable to classical results for
positive. Thus Eqs.(23) and (24) are written so that the sign ofeach diploid viability selection. Importantly, tun 0. Therefore, all of the
term indicates whether it favors A (+ ) or disfavors A (—) when conclusions concerning the ultimate fate of the cooperative type
the denominator is positive. We do this to facilitate the analysis of A in the population, based on the sign of the change in frequency.
large n, in which case a(n) — c(n) and b(n) — d(n) will come to be will be the same whether one appeals to Eq. ( I ) or Eq. (27).
dominated by the terms involving the largest non-unit eigenvalue. Each of the n-step payoffs a(n), b(n), c(n) and d(n) depends on
Another way to write Eqs. (23) and (24) is two of the non-unit eigenvalues, and each eigenvalue is raised to
a2" — an
on) — c(n) = (a — ao)° (c do)
(bcr cag - the power n. Thus a(n), b(n), c(n) and d(n) all decrease to zero as n
tends to infinity. Surviving more steps is less likely than surviving
a2 — ao be —do fewer steps. As a consequence, the two key fitness differences.
+ a; — (25) a(n) — c(n) and b(n) — d(n), and the instantaneous rate of change.
_4 2* — 4 also approach zero in the limit 17 -. co. We study the approach
b(n)— d(n)= (b — ao)(kr (d do) to this neutral limit in order to understand whether increasing n
bc ao d2 — do
fundamentally alters the prospects for cooperation. For example.
+ ao — d; (26) if ic < 0 when n = 1 but the neutral limit z = 0 is approached
from above, then there exists a value of n beyond which k > 0. In
which brings attention to the possible survival value of having a
this case. the single-step game favors the non-cooperative type B
partner and of being A versus B without a partner. Thus, a — ao and
but large-n games favor the cooperative type A.
c — do in Eq. (25) are the increments to the survival probabilities
In the following subsections, we describe four main categories
of A and B when each has partner A compared to when they are
of large-n. or prolonged, survival games. These are characterized
alone. Likewise. b — ao and d — 4 in Eq. (26) are the corresponding
both in the usual way by the relative values of a, b, c and d, that
increments for A and B with partner B versus alone. Note that the
is by the structure of the single-step game. and by the rank order
fractions multiplying these increments are always positive. All else
of non-unit eigenvalues a2, bc, d2 ao and do. We have defined the
beingequal, a(n)—c(n)increases witha—ao > 0 but decreaseswith
cooperative strategy A throughout by a > d, which guarantees that
c — do > 0, and b(n)—d(n)increases with b — ao > 0 but decreases
a2 > d2. Thus d2 will never be the largest non-unit eigenvalue. The
with d-4 > O. Negative increments have the opposite effects. For
first two types of prolonged survival games we describe are those
example,ifB suffers by having aB partner compared to being alone,
for which a2 is the largest and those for which bc is the largest.
then d—do < 0. which in turn favors A via the difference b(n)—d(n). The third and fourth types of prolonged survival games are ones
The last two terms of both Eqs. (25) and (26) quantify the n-step in which lone individuals survive with high probability. Simplifi-
effects of differences in the loner survival probabilities, ao and do. cations emerge when 17 is large because the n-step payoffs become
If ao > do the contribution to both a(n) — c(n) and b(n) — d(n) is dominated by their largest terms. We present approximations for
positive, and if 4 < do it is negative. large n, showing just the leading terms ofa(n)—c(n)and b(n)—d(n),
These five possible increments to individual survival, namely and ofit.
a —ao, b—ao, c —do, d—do and ao—do.in Eqs.(25)and (26 ) are helpful
for understanding some of our results and the structure of survival 11. Games in which cooperation will prevail
games generally. However, it is also clear from the additional
presence of the pair-state eigenvalues in Eqs. (25) and (26) as well The first case we consider is when having a partner significantly
as in Eqs. (23) and (24). that these five increments do not entirely enhances survival and it is theAA type not theAB type that survives
determine the prospects for cooperation. The relative magnitudes best This is case in which a2 is the largest non-unit eigenvalue:
of the five eigenvalues will also be important. This may be seen in a2 > bc, ao, do. Thus, the probability that both members of an
the denominators in Eqs. (25), (26), (23) and (24), which contrast AA pair survive a single iteration is greater than the corresponding
the survival of pairs to the survival of loners: a2 —ao, be —ao. bc —do, probability for any other pair and for either type of lone individual.
d2-4. The precedingexpressions, Eqs.(23)and(24). are especially The condition a2 > bc may be true of any kind of two-player
useful for predicting the structure of the game when n is large. game, but the chance it is depends on the game. One way to
quantify this is toconsider the total parameter space of two-player.
3. Four types of prolonged survival games single-step survival games. Because a, b. c and d are probabilities
and here it is assumed that a > d, this space is equal to half of a
Here, we present analytical results for large n and use our four-dimensional hypercube. Further, since a > d implies a2 > d2,
exact results to illustrate how the prospects for A depend on n for there are just three possible relations of the pair-state eigenvalues,
intermediate values. The analysis of large n allows us to answer a2, bc and d2. Either bc > a2, a2 > bc > d2 or d2 > bc. The latter
questions such as: Is there a number of iterations beyond which A two satisfy the condition a2 > bc. Table 2 lists the proportions
is unambiguously favored? More generally, we ask how the game of the total parameter space satisfying the criteria for each type
might change for A, for better or for worse, as the number of of single-step game. In addition, Table 2 shows the percentages
EFTA00810747
44 J. WaRefry and M. Nowak/ Theoretical Population Many 125 (2019)38-55
Table 2
Partitioning of the four-dimensional hypercube into fractions meeting the game conditions in the first
column. The types of single-step games are abbreviated PD, SH. HD and HG for Prisoners Dilemma,
Stag Hunt, Hawk-Dove game, and Harmony Game. Exact results were obtained by integration in
Mathematica (Wolfram Research. Inc., 2018). Percentages are rounded to the nearest 0.1%. Note that
in all cases a > el by definition, so it is always true that 02 > d2.
Order of pair-state eigenvalues
Game type Proportion be >a, a2 > bc > d2 el? > bc
PD: a <c,b<d 1/12 10% 40% SO%
with a > (b + c)/2 (3/4 of 1/12) 0% 40% 60%
with a > (b + c)12.d < (b+ c)/2 (1/2 of 1/12) 0% 60% 40%
SH: a>c,b<d 1/4 0% 11.1% 88.9%
HD: a < b > d 1/4 80% 20% 0%
HG: a>c,b>d S/12 10% 663% 23.3%
of the game-specific parameter regions corresponding to each of In this case, the large-n game becomes a Harmony Game in whichA
the three possible relations of the pair-state eigenvalues. So, for is unambiguously favored. On the other hand, if the second largest
example, 90% of PD-type games have az > bc, compared to 20% of eigenvalue is dz, then from Eq. (24) we have
HD-type games. — d°
d
When the single-step game is a canonical Prisoner's Dilemma,it b(n)— d(n) dea e0. (31)
crz — do
is always true that az > bc. This is due to the assumption that the
reward payoff must be larger than the average of the temptation In this case, the large-n game becomes or remains a Stag Hunt
payoff and the suckers payoff (see, e.g. Rapoport and Chammah. game, so A does not become unambiguously favored. The chances
1965; Axelrod, 1984), in which case we have of being in either of these two sub-cases are given in Table 2.
Similar arguments can be applied when ao or do is the second-
b c +(b c) 2 largest non-unit eigenvalue. Then Eq. (24) shows that for large iv,
02 > (- )2- bc (- > bc. (28) b(n) — d(n) > 0 if ao is the second-largest, and b(n) — d(n) < 0 if
2
do is the second-largest.
In what follows, it will be important to know which is the second- Regardless of which is the second-largest non-unit eigenvalue,
largest non-unit eigenvalue, especially in the consideration of fi- if az is the largest then a(n) — c(n) will be much greater than
nite populations in Section 4. Thus, the two cases az > bc > dz b(n) — d(n) when n is large. This may be expressed as
and d2 > bc are distinguished in Table 2. We find that canonical
Prisoner's Dilemmas are 40%az > bc > dz and 60%d2 > bc. If b(n) — d(n)
lim (32)
we also require that the punishment payoff must be less than the 1?- .00 a(n) — c(n)
average of the temptation payoff and the sucker's payoff (e.g. see Thus, when n is very large, the advantage in survival that A has
p. 219 of Cressman. 2005). this 40 : 60 split is reversed. over B when the partner is A will be much greater than whatever
It would be possible to expand Table 2 by including ao and do difference there is in survival between A and B when the partner is
and integrating over the six-dimensional space of all parameters. B. One may argue from an evolutionary standpoint that the large-n
There would be more than three relations among the five non-unit Stag Hunt game, with a(n) — c(n) in Eq. (29) and b(n) — d(n) in
eigenvalues. We do not pursue this here. For the prolonged games Eq. (31), will be a very relaxed cooperative dilemma. Specifically.
considered in this section and in Section 3.2, it is taken for granted owing to Eq. (32), a large-n Stag Hunt of this sort will have its
that neither ao nor do is the largest non-unit eigenvalue.In contrast. unstable polymorphic equilibrium x in Eq. (2) close to zero, with
in Sections 3.3 and 3.4 it is taken for granted that one of ao or do is the result that A will be favored over most of the range of x.
the largest non-unit eigenvalue or they both are and they are equal. Finally, when n is very large the replicator equation, Eq. (1),
If we were to include a0 and do in Table 2, we expect they would becomes
often be larger than az and bc due to the fact that these pair-state a — a°
k rr x2(1 — x)a2"— >0 for all x e(0, 1). (33)
eigenvalues are products of probabilities. 0
There is just one term in Eqs. (19) through (22) which includes We conclude that, if n is large enough in the case of this first type
the factor a2..corresponding to what is assumed here to be the of prolonged survival game, the more cooperative type A will be
largest non-unit eigenvalue, az.It is in the expression for a(n).Thus. uniformly favored in an infinite population. This result requires
we have only that az is the largest non-unit eigenvalue. It is robust to
a(n) — c(n) r a2„ a2 differences in the loner survival probabilities 00 and do. As long as
ao > 0 (29)
az is large enough, the non-cooperative type B cannot be rescued
when n is very large. Eq. (29) gives the approximate value of a(n)— by an advantage in loner survivability. Table 2 shows that az > bc
c(n) as it approaches zero in the limit n co. This result shows for the great majority of possible single-step survival games, the
exception being games of the Hawk-Dove type, of which only 20%
that whatever value or sign a(1) — c(1) = a — c might have in a
will have this property.
single iteration, there exists a value of n above which a(n) — c(n)
Fig. 3 illustrates how the two key differences in payoff. a(n) —
will be greater than zero. c(n) and b(n) — d(n), change as n increases for two examples based
The leading term in the other key difference. b(n) — d(n), will on the Prisoner's Dilemma. In Fig. 3A, the survival probabilities for
depend on which of bc, dz. 00 or do is the next-largest eigenvalue. individuals with partners are a = 0.8. b = 0.6, c = 0.9. d = 0.7.
Consider, for example, a game which strongly enhances survival, Thus. the cooperative type A incurs an 11% loss of fitness compared
such that az, bc, d2 > ao, do. If bc is the next largest eigenvalue to B when the partner is A and a 14% loss when the partner is B.The
after az, then from Eq. (24) we have survival probabilities for loners are much smaller and identical:
ao = do = 0.3. The eigenvalues are az = 0.64. bc = 0.54.
b(n)— d(n) e- (bcr bc — ao > 0. (30) = 0.49, ao = 0.3 and do = 0.3. This game starts as a Prisoners
b ao
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J. Wakeley and M. Nowak/Theoretical Population Biology 125 (2019)38-55 45
A B
Payoff Difference
Number of iterations. n Number of Iterations, n
fig. 3. Values of the two key differences.a(n) — c(n)and b(n) — d(n).as a function of the number of iterations. for two different survival games which are Prisoner's Dilemmas
when n = 1. Panel A: a = 0.8. b =0.6,c =0.9.d= 0.7 and ao = do = 0.3. Panel 6: a= 0.9.6 =0.8,c =0.95. d = 0.85 and ao =do = 0.65.
A 0.04 PO HD HG B 0.04 PD • SH HG
8 0.02 8 0.02
0 0.
,go
z -0.02
• a(n)-c(n)
-0.02
• a(n)-c(n)
-0.04 • b(n)- d(n) I -0.04 • b(n)-d(n)
0 . - 0.06 (5 -0.06
- 0.08 -0.08
1 10 20 30 40 SO 60 70 80 1 10 20 30 40 60 60 70 80
Number of Iterations, n Number of Iterations, n
Fag. 0. Values °IG(n) — c(n) and b(n) — d(n) over n = 1...80 iterations for two games which begin as Prisoner's Dilemmas at n = I. In both cases, the loner survival
probabilities are ck, = 4 = 0.9. PanelA: a = 0.97.6 = 0.94. c = 0.99,d = 0.95; these are the same as in Fig. IA and D. PanelIt a = 0.9733.6 = 0.94.c = 0.99, d = 0.9567:
this differs from panel A only in that a and d are spaced evenly between c and b.
Dilemma (PD) when n = 1. For intermediate numbers of iterations. how an increase in this sort of environmental challenge affects the
specifically n = 3 and n = 4, the game changes to one in which A is outcome of the game. Single-step survival probabilities are smaller
disfavored when rare (b(n) — d(n) < 0) but favored when common in Fig. 3A, so we would say that the environment is harsher in
(a(n) — c(n) > 0), as in the Stag Hunt (SH). Then as n grows it Fig. 3A than in Fig. 3B. Comparing the two shows that increasing
becomes a game in which A is uniformly favored, as in the Harmony this kind of adversity causes the cooperative type A to become
Game (HG). unambiguously favored (HG) sooner, that is for smaller n.
Fig. 3B displays results for a very similar game, but one in which Fig. 4 shows how a(n) — c(n) and b(n) — d(n) change as the
the single-iteration probabilities of individual survival are shifted number of iterations increases for two Prisoner's Dilemmas with
closer to 1 by a factor of 1/2. That is, a = 0.9, b = 0.8. c = 0.95. survival probabilities even closer to 1. In Fig. 4A. the game at n = 1
d = 0.85 and ao = do = 0.65. Now the eigenvalues are a2 = 0.81. is identical to the example in Fig. IA and ID. Again, the payoffs in
be = 0.76, d2 = 0.7225. ao = 0.65 and do = 0.65. Overall, the this game follow the classical spacing (R = 3, S = 0, T = 5. P = 1)
picture is similar to Fig. 3A, with the three phases PD then SH then of Axelrod (1984). For comparison, the game in Fig. 4B has the same
HG. But now in moving from n = I ton = 2. the selection against value of the temptation payoff (c = 0.99) and the sucker payoff
A becomes stronger rather than weaker. This is more in line with (b = 0.94) but has reward a and punishment d spaced evenly
the usual notion of iterated games, in which payoffs are assumed between these, as was the case in Fig. 3. 1n both Fig. 4A and 4B,
to accrue additively. In survival games, however, this decrease the loner survival probabilities are ao = 4 = 0.9. Both show
cannot continue because all games become neutral as n approaches the phenomenon of a worsening dilemma (greater disadvantage
infinity. for A) at small n. then a switch to a relaxed dilemma and finally to
Fig. 3 may be compared to Fig. 4 (Model 2AIII) of De Jaegher a Harmony Game. In Fig. 4B, the intermediate, relaxed dilemma is
and Hoyer (2016). with their number of attacks being analogous a Stag Hunt game, as in Fig. 3. In Fig. 4A, the intermediate, relaxed
to n. A point of contrast between our model based on multiplying dilemma is instead a Hawk-Dove game. Eqs. (25) and (26) are
single-step survival probabilities and the behavioral and ecological helpful in understanding the difference between Fig. 4Aand Fig. 48.
scenario, Model 2 of De Jaegher and Hoyer (2016) is that in our In moving from Fig. 4A to Fig. 48, the increment a — ao in Eq. (25) is
model the payoff differences a(n) — c(n) and b(n) — d(n) may be boosted by 0.0033 and the increment d — 4 in Eq. (26) is boosted
non-monotonic. as they are in Fig. 3, whereas these are always by 0.0067. This increases a(n) — c(n) and decreases b(n) — d(n).
monotonic in Model 2 of De Jaegher and Hoyer (2016). We will Fig. 5 shows how a(n) — c(n) and b(n) — d(n) change as n
return to Model 2 ofDeJaegher and Hoyer (2016) and make further increases for examples of the Stag Hunt and the Hawk-Dove game.
comparisons in the Discussion. Parameters are as in Fig. I with the addition of ao = 4 = 0.9
Because survival probabilities decrease with each iteration. n is for both models. As with the examples in Fig. 4, these are cases
a measure of the adversity faced by individuals, or the harshness in which a2 is the largest non-unit eigenvalue. so Eqs. (29), (30)
of the environment Mother way to measure adversity is directly and (31) apply. In contrast to what is seen in Fig. 4, one or the
in terms of single-step survival probabilities. Adversity is greater other of a(n) — c(n) and b(n) — d(n) is still negative in Fig. 5 even
when a, b, c, d, ao and do are smaller. Fig. 3 provides an example of at n = 100. From n = 1 to beyond n = 100, these remain a
EFTA00810749
46 J. Wake!ey and M. Nowak/Theoretical Population Biology 125 (2019)38-55
A Stag Hunt B Hawk-Dove
0.15 • a(n)-c(n)
0.4
▪ b(n)-din)
0.3 Od
0.2 OM
0.
-0.05
-0.2 -0.1
20 40 80 80 100 20 40 60 80 100
Number of Iterations. n Number of Iterations, n
Fig. 5. Values of o(n) — c(n) and b(n) — d(n) over n = 1... 100 iterations for two games whkh begin as a Stag Hunt and as a Hawk-Dove game at n = I. In both cases, as
in Fig. 4, the loner survival probabilities are cio = do = 0.9. Panel A: a = 0.99. b = 0.94. r = d = 0.97; these are the same as in Fig. IB and E. Panel El: a = 0.97.6 = 0.95.
c = 0.99. d = 0.94: these are the same as in Fig. IC and F.
A B
0.005
0. s h.
0
-0.005 C 4 1
4, -0.005
4.)
-0.01 -001
60
O. 005 o.
0.2 0.2
0.4 0 OA
0.8
x 0.8 15 n x
Fig. 6. Picas of k for the models in Fig. 4. that is for two diferent Prisoner's Dilemmas at n = I. Panel A: a = 0.97,8 = 0.94.4 = 0.99. = 0.95 and ao = do = 0.9. Panel It
a = 0.9733.6 = 0.94, c = 0.99. d = 0.9567 and ao = do = 0.9. In both panels. the thick contour line is drawn at it = 0, which corresponds to the polymorphic equilibrium
of Eq. (2) for each value of rt. For simplicity of presentation, we plot the surface as a smooth function of n, whereas in reality it is discrete.
Stag Hunt and a Hawk-Dove game. In the Stag Hunt of Fig. 5A, the in the picture for the largest values of ri in Fig. 7, in both cases A
next-largest eigenvalue is d2, so b(n) — d(n) will remain negative. will become favored if n is large enough. In the Stag Hunt of Fig. 7A
However, as can already be seen in the figure. it will be much or 5A, ic 0 as ri co. In the Hawk-Dove game of Fig. 76 or 5B. it
smaller in magnitude than a(n) — c(n). In the Hawk-Dove game of will exit the biologically relevant interval and become larger than
Fig. 56. the next-largest eigenvalue is bc, so b(n) — d(n)will remain one when a(n) — c(n) first becomes positive, when n = 615.
positive. But since a2 is the largest non-unit eigenvalue, a(n) — c(n)
will become positive (when n = 615. from numerical solution) and 12. Games which preserve noncooperative behaviors
eventually will become much larger than b(n) — d(n).
Another way to view the results presented in Figs. 3-5 is in Here we consider the case that the game enhances survival
terms of * rather than a(n) — c(n) and b(n) — d(n). Fig. 6 shows this significantly and it is AB that fares best. Thus. bc is the largest non-
for the examples of Fig. 4. Now the overall shape of * can be seen unit eigenvalue. Table 2 shows that this will occur most readily
as it moves from ri = 1, where it is a Prisoner's Dilemma identical when the single-step game is a Hawk-Dove game. It might also
to what is depicted in Fig. ID. to ri = 60, where it is a Harmony occur for Prisoner's-Dilemma type games, but only if the canonical
Game. In both panels, the thick contour line traces z = 0. showing assumption a > (b t c)/2 is violated. It will not occur when the
the polymorphic equilibrium in Eq. (2) when it exists. In Fig. 6A, single-step game is a Stag Hunt. Here, again, we assume that having
this equilibrium enters at x = 0 and exits at x = 1. In between, a partner significantly enhances survival, so bc > a0, do.
the shape of z is like that of Fig. 1F, namely similar to the Hawk-
There are two terms in Eqs. ( 19) through (22) which include the
Dove game in which A is favored when rare and disfavored when
common. In Fig. 6B, the equilibrium enters at x = 1 and exits at factor (bc)". They are in the expressions for b(n) and c(n). For very
x = 0. Here the shape of z for intermediate n is like that of Fig. IE. large n we have
namely similar to the Stag Hunt in which A is disfavored when c—
rare and favored when common. Note that although a(n) — c(n) a(n)— c(n) —Cory — do 0 (34)
bc — do
and b(n) — d(n) vary non-monotonically in these cases (Fig. 4), the —
equilibrium A is monotonic inn. b(n)— d(n) (bc)" > 0. (35)
bc
b —aoao
Fig. 7 shows how the shape of * changes as the number of
iterations increases for the Stag Hunt and the Hawk-Dove game Thus, survival games of this sort either stay or become Hawk-Dove
depicted in Fig. 5. Note that to aid in visualizing these surfaces. games as n increases. In addition. a(n) — c(n) and b(n) — d(n) will
the viewpoints are different in the two panels and the ranges of be of the same order of magnitude as n tends to infinity. In the
n are different than in Fig. 5. As with the Prisoner's Dilemmas in previous section. where AA survived best, increasing ri converted
Figs. 3 and 6, these are both cases in which a2 is the largest non- single-step Prisoner's Dilemmas. Stag Hunts and some Hawk-
unit eigenvalue. Following the discussion of Fig. 5, although the Dove games into progressively more relaxed cooperative dilemmas
polymorphic equilibria traced by the thick contour lines are still until, eventually, A became favored. Here. Eqs. (34) and (35) show
EFTA00810750
J. Wakeley and M. Nowak/Theoretical Population Biology 125 (2019)38-55 47
A B
0.015
0.01
0.005
5( 0.
-0.005
0 1.
Fig. 7. Plots of* for the models in Fig. 5. For the n = 1, Stag Hunt in panel A: a = 0.99, b = 0.94.c = d = 0.97 and no = do = 0.9. For the n = 1. Hawk-Dove game in panel
B: a = 0.97, b = 0.95, c = 0.99, d = 0.94 and ao = do = 0.9. In both panels, the thick contour line is drawn at i = 0, which corresponds to the polymorphic equilibrium it
of Eq. (2) for each value of n. Note that the viewpoints and the ranges °Info; the two panels are different.
A 0.4
B
0.2
a
0.
-0.4
20 40 60 80 100 120
1.
Number of Iterations, n
Hg. B. Hawk-Dove type game in which be is the largest eigenvalue: payoffs a = 0.95, b = 0.97.c = 0.99, d = 0.94 and ao = do = 0.9. The thick contour line in B shows
k = 0, which stabilizes to ilk = 0.5625 as n increases.
that single-iteration Hawk-Dove games in which AB survives best thick contour line) as n increases, even as the game first intensifies
are robust to such alteration. Eqs. (34) and (35) also show that if for intermediate n then approaches neutrality for large n.
a survival game is a non-canonical Prisoner's Dilemma at n = 1,
such that bc rather than a is
largest non-unit eigenvalue, the 13. Games ruled by loner survivability
n-step game will eventually become a Hawk-Dove game rather
than a Harmony Game. In both of the previous sections. it was assumed that having
When bc is the largest non-unit eigenvalue, the large-n approx- a partner provided a substantial boost to survival. In this section
imation for the change in frequency is and the next, we consider cases in which having a partner does
not enhance survival. If either a lone A or a lone B has the highest
is Az x(1 — x)(bc)" (— c — do x+ —ao
b (1 x)). (36) probability of surviving each iteration of the game, then either a0
be —do bc — ao or do is the largest non-unit eigenvalue. Two terms in Eqs. (19)
We deduce that, for large n, is > 0 if x < it& and it <Olin. icon through (22) include the factor ag—they are in the expressions
where for a(n) and b(n)—and two terms include the factor dg—they are
in the expressions for c(n) and d(n). If ao is the largest non-unit
(b — 00)/(bc — Go) eigenvalue, then for very large n we have
itbr = (37)
(b — ao)/(bc — ao) + (c — do)/(bc — do)
This frequency cutoff may be interpreted as the probability, when n a(n) — c(n)-- ao 0(1 a ) > 0 (38)
00 — 02
is large, that if AB plays the game and only one individual survives. b(1 — c)
it is the A individual. For reference, if a0 and d0 are both very small. b(n)— d(n)-- ao >0 (39)
then Eq. (37) reduces to b/(b + c). If the population frequency of a0 —bc
A is smaller than this probability in Eq. (37), then A is favored. and if do is the largest non-unit eigenvalue, we have
otherwise it is disfavored. This cutoff is of course equal to the cr c(1 — b)
limiting (ri oo) value of Eq. (2) when bc is the largest non-unit a(n) — c(n) (40)
° do — be < °
eigenvalue, which is stable in this case.
d"nd(1 — d)
Fig. 8 depicts both how a(n) — c(n) and b(n) — d(n) change and b(n)— d(n)-- ., — do _ d2 e0. (41)
how ic changes as n increases fora Hawk-Dove example in this case.
It may be more easily seen in Fig. 8B that this example remains Thus. if single individuals of one type have a higher probability
a Hawk-Dove game with a stable polymorphic equilibrium (the of survival than single individuals of the other type and than any
EFTA00810751
48 J. Wake!ey and M. Nowak/Theoretical Population Biology 125 (2019)38-55
A 0.12 HO SH PD B
0.025
S 0.09
Payoff Difference
C • a(n)-c(n) 0.
0.06 b(n)-d(n) -0.025
15 0.03 -0.05
a
0. -0.075
-0.03 -OA
5 10 15 20
Number of Iterations. n Number of Iterations, n
flg.9. Values of o(n) — c(n) and b(n) — d(n) as n increases for two games which begin as a Harmony Came and as a Hawk-Dove game at n= 1. Panel A: a= 0.8, b= 0.5,
c= 0.7, cl= 0.4 and ao =do = 0.9. Panel B: Hawk-Dove a = 0.93.6 = 0.91.c = 0.954 = 0.90 and ao = = 0.95.
pair of individuals, that type will become favored in the population enhance survival but does cause payoff differences - and is the
as the number of iterations grows, regardless of the structure of only source of these differences - there is no expectation that the
pairwise interactions in the single-step game. The corresponding prospects for cooperation will improve as the number of iterations
approximations for k can be inferred from Eqs. (38) through (41). increases. These cooperative dilemmas may intensify rather than
becoming more relaxed.
3.4. Games with a pairwise survival deficit
4 Evolutionary dynamics in a finite population
A related but probably more interesting case is when single
individuals have higher survival probabilities than any pair of All populations are finite, so changes in the frequency of A will
individuals but the loner survival probabilities are identical. Then be stochastic rather than deterministic. Here we describe these
having a partner does not enhance survival but the two-player changes for a particular population model and check the validity
game may still provide an advantage to one strategy or the other. of our previous conclusions based on the deterministic predictions
In this case ao = do is the largest non-unit eigenvalue. When n is for k (or .dx). In a finite population, xis discrete, not continuous. If
very large, using Eqs. (23) and (24) and substituting ao for 4, we N is the population size and K is the number of A individuals. then
have K E (0, 1 N - 1, N) and x E (0, 1/N (N - 1)/N, 1).We
a(n) - c(n) a(1 - a) c(1 — b)] study the process ofjumps inK orx when both death and reproduc-
4 [ (42) tion are stochastic. We continue to assume that the survival game
at, ao _ bc
is the only source of fitness differences and that the population is
b(1 — c) d(1 — d)i • well-mixed in the sense that partners are chosen at random.
d(n) 4 [— be (43)
b(n) — ao — ao — d2 Due to the relative simplicity of its transitions and the ease
Whether these differences are greater or less than zero will depend with which the survival game may be embedded within it, we
on which of the two terms in the bra kets is larger in absolute base our model on the haploid population-genetic model of Moran
value. This situation, in which the game is played starting in the (1958).The standard version ofthe Moran model pairs single births
pair state with a survival deficit, is similar in spirit to the way the and deaths such that the population size remains constant. In the
Prisoner's Dilemma was originally formulated, with two individu- absence of selection, each individual has probability 1/N of being
als in custody, each wanting to get out. Here, as in Section 3.3, we chosen to reproduce in a given time step, and a I/N chance to
do not show the corresponding result for k, which can be inferred die. The individual chosen to reproduce makes an offspring which
from Eqs. (42) and (43). replaces the individual chosen to die. When selection is included.
Consider the case of a strong deficit, specifically with ao = do it usually acts by modifying the probability an individual is chosen.
not too small and all of a, b, c and d close to zero. Then, neglecting now based on its fitness, either to reproduce or to die.
terms of a2, be and d2 which will be even smaller, Eqs. (42) and (43) We. instead, consider a model in which two randomly chosen
become individuals play the survival game. Players are chosen without
replacement from the population. This precludes self-interaction.
a(n) — c(n) 4 -1(a — (44) which is appropriate because we wish to model two individuals
b(n)— (12 — 6). (45) being sequestered from the rest of the population for a period
of time. When the n iterations of the game are finished. both
Thus, with a strongdeficit, the results for large n will beof the same individuals may be alive, one may be alive or both may be dead.
type as the results for n = 1. This is the only source of death in the population and the only
When the deficit is milder, no simple approximations for Eqs. place in the life cycle where selection acts. In each time step, these
(42) and (43) are available, but numerical analysis shows that the 0, 1 or 2 deaths are compensated by the same number of births.
conclusions of Section 3.1 can be reversed. Fig. 9 shows two exam- All individuals have an equal chance to reproduce, including the
ples ofhow a(n) - c(n) and b(n) - d(n) may change as n increases, two who play the game. Thus, parents are sampled at random with
converting a single-step Harmony Came and a single-step Hawk- replacement from the population. Finally, offspring inherit their
Dove game into Prisoner's Dilemmas. In both examples, ao = 4 parent's type without modification, i.e. there is no mutation.
is the largest non-unit eigenvalue. In Fig. 9A, the game becomes a Let K be the current number of A individuals. After one time
Stag Hunt for intermediate values ofmin Fig. 9B. the game changes step, the number is K', which will differ from K by at most 2 and
directly from a Hawk-Dove game into a Prisoner's Dilemma as is bounded by 0 and N. The numbers of A individuals in a series
n increases. Thus, when having a partner does not significantly of time steps forms a Markov chain with an (N + 1) x + 1),
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J. Wakeley and M. Nowakl Theoretical Population Biology ITS (2019)38-55 49
pentadiagonal transition probability matrix. Because there is no of N the deterministic prediction is incorrect The error comes
mutation. the states K = 0 and K = N are absorbing.The transition from overestimating the importance of AA and BB pairings in the
probabilities are computed as products of three terms: one for the infinite-population model by implicitly allowing self-interaction.
sampling of a pair of individuals to play the game, one for the Our aim here is to reassess the conclusions of the previous section
outcome of the game and one for the sampling of parents. In all, in light of such differences and especially in light of the fact that
we have A can be fixed or lost from a finite population regardless of the
N—KN—K—I KK value of nein Criteria for A being favored in a finite population
PK.K — Prob(BB 0)— (46)
N—1 NN are generally based on the probability it reaches fixation starting
N—KN—K-1 at K = 1 versus the probability it is lost starting at K = N - 1
PK.K-E1 — (Nowak et al.. 2004; Lessard. 2005). If the probability of fixation of
N N—1
K — Ki A is greater than the neutral probability I/N and the probability
x [Prob(BB B) + Prob(BB 0)2N — of loss is less than 1/N, we might conclude that A is favored.
N N
When selection is weak, a number of analytical results for fixation
KN —K probabilities and times in evolutionary games are available (Wu
-I- 2
NN— I et al.. 2010). Alternatively, in models with mutation the decision
KK as to whether A is favored can be made by comparing the expected
x [Prob(AB A)— + Prob(AB —t• — (47)
0)—N N equilibrium frequency ofA under neutrality versus selection(Rous-
K N —K set and Billiard. 2000). When the mutation rate is small, these two
PICK — 2 approaches become identical.
NN—1
In Section 3, we used ic > 0 for all x E (0, I) as a criterion for A
x [Prob(AB B)N — K Prob(AB -o 0)N -
N
—K N
—
— K]
being unambiguously favored. The analogue here is Wiz] > 0 for
all x E (I/N (N - 1)/N). We take this to be a more stringent
KK- 1 criterion than the one based on fixation probabilities. However.
+
NM - 1 from Eqs. (52) and (53), it is clear that even when AA survives best
N K NKi
0)2- and a2 is the largest non-unit eigenvalue, it will not necessarily be
x [Prob(AA A)- K + Prob(AA
N true that 6[44> 0 for all x e (1/N (N -1)/N).In particular.
for the two terminal frequencies, we have
(48)
- - c(n)— d(n)
PICK-2 — Prout.AA -0 0)NNKNNK (49) s(n: K = 1) = b(n) — d(n) (54)
=N N - I N—1
PX.K = I - PK .X+2 PX - PK.K -1 — PK .K-2- (50) and
Although this process is not as simple as the standard Moran On) — fa)
s(n; K = N — 1) = a(n)— c(n) (55)
process, for which a number of exact results are available (Moran, N—1
1962), as a pentadiagonal matrix it may still be amenable to study. When there is only a single A individual, the possible benefit of the
Following our previous analysis ofic, we focus on the change in the AA pair is unrealized. At the other extreme. when there is only one
number of cooperators, AK = K' - K. in particular on the sign and B individual. it is the BB pair that does not matter.
magnitude ofElidiK) which measures the direction and strength of
Therefore, even when a2 is the largest non-unit eigenvalue, it
selection.
will always be possible to find a population size small enough that
The expected value of AK is given by
A remains disfavored even as n tends to infinity. In particular, if
EIAKI =2PK.K+2 + Pg.g PX.K - I - 2PX.K-2- (51) the population consists of just two individuals, there is only one
polymorphic frequency, K = N - K = 1, and we have
Using Eqs. (46) through (50) and simplifying yields
KN —K s(n; K = 1) = b(n) — c(n) ifN = 2. (56)
nAKI — 2
From Eqs. (20) and (21) we have
x (a(n)K — 1 „ ‘ DI K
c(n) + DM ll boo coo = bb — ao (bcy, b(1 — c),.„ c — do (bcy,
N—I N—1 N-1 N —1
d(n)N-K-1/
ro ao - bc bc —do
(52) c(1 — b)d,,
(57)
with a(n), b(n), c(n), d(n) as before in Eqs. (19) through (22). — do — bc °
Because x = K/N, we also have Ekix] = EfAKI/N. Aside from
which will not in general be favorable to A.To illustrate, if we make
the factor of 2, which arises because two individual are chosen to
play the game and possibly die, Eq. (52) shows nearly the same the simplifying assumption that the loner fitnesses are the same
dependence on a(n), b(n), c(n) and d(n) as the deterministic result (a0 = do), then Eq. (57) reduces to
for z in Eq.(I). We define the selection coefficient (bcr - a"
b(n)- c(n) = (b - c) ° if ao = do. (58)
—1 K + N—K bc — Co
s(n; K) = c(n) — bi)
°(n)N-1 N 1 N—I When n = 1, this is simply b - c. Then as n becomes large.
N — K —1 regardless of which eigenvalue (bc or ao = do) is larger, the sign
d(n) (53)
N—1 ' of b(n) - c(n) will be the same as the sign of b — c. One of the
which captures the dependence of E(AK] on a(n), b(n), c(n) and ways in which a game may be considered a cooperative dilemma
d(n) in its entirety. Of course, the sign of s(n; K) determines the is that b e c (Nowak, 2012). Note that b e c in all ofour numerical
sign of ElAK and E(Ax]. examples. When N = 2, none of the conclusions about relaxed
Comparing s(n; K) in Eq. (53) to its deterministic counterpart in cooperative dilemmas based on z and increasing n will hold. Just
Eq. (I) reveals that when N is small or when K is small regardless the opposite: A will be disfavored.
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SO J. Wakefey and M. Nowak/Theoretical Population Biology 125 (2019)38-55
While there is no expectation that conclusions from an infinite- Case II, reconsidered. This is the case in which bc is the largest non-
population model will be accurate for small populations, we ex- unit eigenvalue and the game tends to preserve the less coopera-
pect their heuristic value to hold for moderately large N. In what tive strategy. The finite-population result corresponding to Eq. (36)
follows, we focus on N >> 1. We begin as before by noting that is
our finite-population model collapses to a neutral Moran model so; ic) c — do K b — ao — K 1 ocr
I
in the limit n co. although it would be one in which pairs of
bc — do N — 1 bc — ao N - 1
individuals rather than single individuals are chosen to die and to
reproduce. Again, we answer the question aboutA being favored by for all K = I N - 1. (62)
studying the approach to this neutral limit In our finite-population
Thus, the terminal frequencies x = 1/N and x = 1 — I/N
model, this neutral limit is E[dx] = 0. Then if. for example.
do not require a separate treatment as they did under Case I.
Wax] < 0 when n = 1 but the neutral limit E(Ax) = 0
Here, just as in the infinite-population model, increasing n will not
is approached from above, then there exists a value of n above
fundamentally alter the game. Selection pressure will tend to keep
which E[dx] > 0. We briefly reconsider each type of prolonged
both A and B in the population.
game.
Case Bl, reconsidered. This is the case in which ao or do is the largest
Case 1, reconsidered This is the case in which a2 is the largest non-
non-unit eigenvalue. For these games ruled by loner survivability,
unit eigenvalue and cooperation is expected to prevail. The finite-
we have
population result corresponding to Eq. (33) is
/a(I —a)K — 1 b(I — c)D1 —K\
a—ao K-1 >0
s(n; K) a-- — > 0 for K = 2 N - 1. (59) s(n; K) bc
a2 — ao N 1
for all K = I, N- I (63)
Thus, for n large enough. EWA > 0 for every frequency x = K/N
except for one. We must investigate K = 1 because, for a given if ao is the largest non-unit eigenvalue, and
large value of n, even though a(n) may dominate all other terms
(c(1 — b) K d(1 — d)N — K — 1
when K = 2 N — 1. it is only b(n), c(n) and d(n) that appear in s(n; K) s < 0
s(n; K = 1) in Eq. (54). When n is large the sign and magnitude 4 — brig — I 4 — d2 N-1
of s(n; K = 1) will be determined by the second largest non- for all K = 1 N- 1 (64)
unit eigenvalue. We consider the same two possibilities as before.
namely when either bc or d2 is next-largest eigenvalue, and we if do is the largest non-unit eigenvalue. The conclusions are un-
continue to assume that the loner survival probabilities, ao and do changed in the modified Moran model relative to the infinite-
are small by comparison. population model. Whichever type survives best alone becomes
If the next largest eigenvalue is bc, then for K = 1 we have favored when n is large.
b— o \ Case IV, reconsidered. This is the case in which ao = do is the
so ; K = 1) (kr largest non-unit eigenvalue. For these games with a pairwise sur-
bc — aGo N , 1 bc — do (60)
vival deficit we have
For very small N it could be that Eq. (60) is negative, but it will
ta(I — a) K — 1 c(1 — b) K
be positive for any moderate to large N, making E[dx] > 0 for
x= 1/N. Combining this with Eq. (59), we conclude that here, with An; K) — a2 N — 1 ao - bc — 1
a2 > bc > d2 do, if n is large enough, then Eldx] > 0 for all b(1—c)N —K d(1 — d)N —K — 1\ 4
K=1 N - 1. Previous Figs. 3 and 4 are examples of this case (65)
ao — bc N — 1 ao — d2 N — 1 )
in which A becomes unambiguously favored.
If the second-largest non-unit eigenvalue is '12, we have in general, and
d — do N — 2 lC — 1 N —K dN — K — 1) I
s(n; K = 1) —a- c ici 6 1 <0, (61) An; K) (a c +b ao
N-1 N-1 N— 1 N—I
and EkIxi < 0 when x = 1/N. But. again, for large n it will (66)
also be true that d2" <C al", so the magnitude of the selection
coefficient against A when K = 1 will be small compared to when the deficit is strong. If K = 1, the first terms in the paren-
selection coefficients in favor of A for every other value of K. We theses in Eqs. (65) and (66) disappear, making A worse off when it
state without proof that in this case, if n is large enough, the is very rare. because those terms are positive. When K = N - I,
probability of fixation of A starting from a single copy should be the last terms in the parentheses in Eqs. (65) and (66) disappear,
greater than the neutral probability I/N, and the probability of making A better off when B is very rare, because those terms are
loss of A starting from N — 1 copies should be less than I/N. negative. It is not expected that this will improve the already dim
We conclude that A should be considered favored in this case as prospects for the evolution of cooperative behaviors in this case in
well. which there is no survival advantage to having a partner.
Situations in which one of the loner survival probabilities. ao or
do, is the second largest eigenvalue can be treated similarly. We S. Discussion
do not pursue this in detail, but in Case III below we consider the
possibility that one of these is the largest non-unit eigenvalue, and We have proposed a simple but general, biologically motivated
from that we can infer that nothing beyond the two possibilities survival game. It is a repeated game which always starts with a
above for s(n: K = 1) will arise. That is. as n grows. s(n; K = I) will pair of individuals and includes a fixed number of iterations. Prob-
be either positive or negative but will be very small compared to abilities of survival are its expected payoffs. We have assumed that
s(n; K) which is positive for K = 2 N- 1.Thus, the conclusion multi-step survival is a Markov process, which has consequences
that A becomes favored when a2 is the largest non-unit eigenvalue such as that the game may change stochastically to a loner game
still holds. against Nature if one's partner dies and that all payoffs tend to
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J. Wakefey and M. Nowak/Theoretical Population Biology 125 (2019)38-SS SI
zero as the number of iterations tends to infinity. Results provid- Table 3
ing some insight into the evolution of cooperation are obtained Two models in which individuals of type A and B have the same single-step
probability of survival given the type of their partner, but in which the survival
when the number of iterations is large, including the conversion probability of any individual depends on the partner's type. The format is as in
of cooperative dilemmas into situations in which cooperation is Table I but with an additional column for the case in which an individual no longer
unambiguously favored. has a partner. In the first model having a partner of type A boosts the probability of
Survival is an appropriate, direct measure of payoff (or utility) survival of both types of individuals by an amount t above background (do). In the
in evolution. Our analysis is similar to the analysis of diploid second model having a partner of type B lowers the probability of survival of both
types of individuals by an amount e.
population-genetic models in that we have described interactions Equal-payoff model with A-partner increment:
between individuals only in terms of fitness. What we have called
strategies correspond to the alleles in a diploid population-genetic A B No partner
model. We have assumed that individuals' strategies are fixed. A a = do + e b = do ao =4
B e=do+e d = do do
meaning the same in every step of the game. For this sort of
survival game, our results are general. They hold for any pattern Equal-payoff model with 8-partner decrement:
of payoffs in the single-step matrix in Eq. (3). They can be applied A B No partner
to any biological, behavioral or ecological model for which the A a=do = do — • ao = do
assumption of Markov survival is reasonable. They need not be B c = do d= 4 —• .4
pure strategies, for example. They could be mixed, as in Garay
(2009), so long as they are the same in every step.
Our Markov assumption is twofold: (i) when an individual has a equations and their equivalents, Eqs. (23) and (24). Pairwise sur-
partner, its single-step survival probability depends on its strategy vival probabilities are crucial to understanding the structures of
and on its partner's strategy, and (ii) when an individual is alone. prolonged (large-n) games. which depend strongly on the largest
its single-step survival probability depends on its strategy. An
non-unit eigenvalue of the Markov survival process.
individual's multi-step survival probability is the product of its
In the first example, having a partner of one particular strategy
single-step survival probabilities given its situation in each step.
The model of repeated predator attacks in Garay (2009) is precisely either increases or decreases the survival probability of the indi-
such a Markov survival model.In constructing the matrix in Eq. (3), vidual. but by an amount which does not depend on the strategy of
we have further assumed (iii) that conditional on both of their the individual. We consider the two possibilities shown in Table 3.
strategies, which determine their individual survival probabilities. that either having an A partner increases survival or having a B
the two members of a pair survive each step independently of partner decreases survival. In both cases, the change in survival
one another. If synergistic effects of partnership (Hauert et al.. (+4 or -6)is the same for A individuals and B individuals. All other
2006; Kun et al., 2006) are defined as non-multiplicative, then survival probabilities are equal to a baseline, do. Thus a — c = 0
assumption (iii) precludes synergy within a single step in our and b — d = 0. The single-step game is neutral. Fig. 10 shows how
model. Any synergies in an n-step game result from the Markov a(n)— c(n)and b(n)— d(n)depend on n when do = 0.5 ande = 0.1.
process of survival for a given set of parameters (a, b, c, d, ao. do). In this case, ao = 4 is the largest non-unit eigenvalue. In Fig. 10k
We began with the motivation of Kropotkin (1902), whose a(n)— c(n) > 0 for n ≥ 2 while b(n)— d(n) = 0 for all n. In Fig. 10B.
work focused on vertebrates, but we note here that our model a(n) — c(n) = 0 for all n while b(n) — d(n) e 0 for n > 2. These
is not designed with any particular species in mind. None of our results may be understood with reference to Eqs. (25) and (26).
results rely on individuals possessing the intelligence or decision- with ao = do. In the case of Fig. 10A, a — ao = c — do = f but, owing
making capability of vertebrates. It could be argued that many to the eigenvalues, the positive increment a — 4 is weighed more
fundamental steps in the evolution of cooperation happened long heavily than the negative increment c — 4 when n > 2. so Eq. (25)
before, perhaps many hundreds of millions of years before this gives a(n) — c(n) > 0 for n > 2. Eq. (26) gives b(n) — b(n) = 0
kind of intelligence. The iterated survival game described in Sec- because b — ao = d — 4 = 0. Analogous arguments explain
tion 2 may be applied in a variety of settings, but the evolutionary the case of Fig. 10B. In sum, the more-cooperative A is favored if it
models of Sections 3 and 4 may be better suited to populations unilaterally increases the survival of its partner (Fig. 10A) and the
of single-celled organisms than complicated metazoans, because less-cooperative B is favored ifit unilaterally decreases the survival
they assume haploid genetic transmission and individuals with of its partner (Fig. 10B).
fixed strategies. For the second example, we design an iterated survival game
Kropotkin inferred a connection between cooperation and sur- which expresses key ideas behind Model 2 of De Jaegher and Hoyer
vival under adverse conditions, and our work draws a distinc- (2016) directly in terms of survival. Again, this is a model of a
tion between games in which partnerships enhance survival and number of attacks on a pair of individuals. The individuals are
those in which having a partner is a liability. If there is a fitness
identical in most respects. There is a public good which benefits all
advantage of having a partner, then less-cooperative behaviors
individuals equally, ifit is preserved against attack. Each individual
which are advantageous in each single step of a game may become
disadvantageous as the number of iterations increases. This can be also has a private good which may impart a by-product benefit on
true even if cooperative behaviors are strongly disfavored in the its partner, again if it is preserved against attack The difference is
single-step game, as in the Prisoner's Dilemma (e.g. Fig. 3A). But that cooperators (A) pay a cost and are immune to attacks whereas
if partnerships do not significantly enhance survival, the opposite defectors (B) pay no cost and are susceptible to attacks. Thus,
may occur. In this case, even cooperative behaviors which are defectors may benefit when they are paired with cooperators.
favored in the single-step game can become disfavored as the This is not a survival game because individuals do not die in the
number of iterations increases (e.g. Fig. 9A). attacks. It is Markovian only in that each attack hits one member
We close with a discussion of two examples which illustrate of the pair randomly with probability 1/2. Nonetheless. this behav-
the effects of enhanced survival. We have identified two kinds ioral and ecological model has roughly similar outcomes to those
of enhanced survival: for individuals and for pairs of individuals. we have described here. when n corresponds to the number of
These different boosts to survival are captured by the individual- attacks.
survival increments of Eqs. (25) and (26), and by the presence of Consider a survival game in which the probability an individual
the pair-state eigenvalues of the Markov process in these same survives each attack. or iteration. depends on its type and its
EFTA00810755
52 J. Wakeley and M. Nowak/ Theoretical Population Biology 125 (2019)38-55
A B
0.008 0.008 • a(n)-c(n)
Payoff Difference
a b(n)-d(n)
0.004 0 004
0
11 -0.004 -0 004
a.
-0.008 -0.008
Number of Iterations, n Number of Iterations, n
Fly 10. Values of the two key differences, a(n)- c(n)and LIN - d(n). as a function of the number of iterations. for the two versions of the equal-payoff model depicted in
Table 3, with baseline survival probability do = 0.5 and increment/decrement t = 0.1. Panel A: a = 0.6, b = OS, r = 0.6, d = OS. Panel B: a = 0.5, b = 0.4. r = 0.5,
d= 0.4. Both panels: ao = do = 0.5.
partner's type as follows.
PD SH HG
A with A: (67) 0.
I -0.01
A with B: b= do g - u (68)
co aa
-0.02 e • a(n)-c(n)
B with A: c= do -Fg-l-u (69) pi
• • b(n)-d(n)
t -0.03 •
B with B: d=d o tg (70)
0. -0.04 • •
A alone: ao = d,3 — u (71) ep .
-0.05
B alone: do (72)
1 10 20 30 40
Here u is the cost of being a cooperator. v is the benefit an in-
dividual receives when its partner is a cooperator and g is the Number of Iterations, n
added benefit of simply having a partner. The parameters do and
Fig. 11. Values of the two key differences, a(n)— c(n)and b(n) — d(n)as a function
g might represent the private and public goods in De Jaegher and
of the number of iterations. for the game with payoffs shown in Table 4.
Hoyer (2016). The general versions of our model and Model 2
of De Jaegher and Hoyer (2016) each have seven free parameters.
Table 4
whereas the model above has five. Numerical example of the model defined in Eqs. (67) through (72), assuming that
For this model a —c = b-d = -u < 0, so the cooperative type A do =0.8.0 = 0.02. = 0.03andwithg = (I + Nir o — O/2 — do x 0.B.
is disfavored in the single-step game.In addition. ao —do = —u < 0 A B No partner
which suggests that the cooperative type A might be disfavored for A a = 0.94 = 0.91 00 = 0.78
larger n. However, considering the terms in Eqs. (25) and (26) we 8 c=0.96 d=0.93 do = 0.80
havea—ao =c —do =g+v> 0 andb—ao =d - do =
g > 0. If a2 is the largest non-unit eigenvalue then a(n) — c(n) will
eventually become positive, and if bc is the next-largest eigenvalue
then b(n) - d(n) will also eventually become positive. are immune to attack in Model 2 of De Jaegher and Hoyer (2016).
A strong criterion for partnerships enhancing survival would be Here, instead, cooperation becomes favored as n increases due to
that a2, bc and d2 are all greater than do. A weak criterion would the subtle advantages the more cooperative type A accrues because
be that only a2 > do. If we adopt the strong criterion and further AA pairs survive best and AB second best among the three possible
assume that a2. bc > d2. then the game would enhance survival if pairings, despite the direct disadvantage of A compared to B in AB
d2 > do. This implies that pairs as well as in the loner state.
Rather than considering that individuals might change their
g> Vito - do. (73) strategies between steps of the game in response to their part-
ners, we have focused on the evolution of hardwired, non-reactive
We have assumed throughout that a, b,c and dare all less than one.
strategies within populations. Among other results, we find the
so it must also be true that
conditions under which cooperation will increase in frequency
g < 1 — do — u. (74) over time in both finite and infinite populations despite being
disfavored in every step of the game. In the case of a finite pop-
For the sake of illustration, set g equal to the midpoint between
ulation, this conclusion is based on a strong criterion for selective
these two extremes, so that g = (1 + — u)/2 — do. Assume
advantage, that the expected change in frequency of cooperation
further that v > u, which means that the single-step game is a
is positive over the entire range of possible frequencies.
Prisoner's Dilemma. Using the particular values do = 0.8. u = 0.02
and v = 0.03 gives the survival game shown in Table 4.
One would not immediately guess that the more cooperative Acknowledgments
type A would ever be favored in such a game. But as Fig. 11
illustrates, this does become true as the number of attacks in- We thank Sabin Lessard and two anonymous reviewers for
creases. For n > 32 both a(n) — c(n) and b(n) - d(n) are greater comments which greatly improved the work We also thank Jo-
than zero, though clearly the prolonged game yields rather weak hannes Wirtz for posing a question which led to the model pre-
selection in this particular example. Note that we have not granted sented in Table 3 and Fig. 10. This work was supported in part by
A any obvious advantage. As previously mentioned, cooperators grants N00014-16-1-2914 from the US Office of Naval Research.
EFTA00810756
J. Waketey and M. Nowak/Theoretical Population Biology 125 (2019)38-55 53
55832 from the John Templeton Foundation and W911NF-18-2- 2d(1 — d) 2d(1 — d)1T
0265 from the US Defense Advanced Research Projects Agency to I4 [0, 0, 1, 0, (88)
= 4 — d2 , 1 4 — d2 _I
Martin Nowak. 0,0,0,1,0, 1]T
15 = (89)
Appendix /6 = (0, 0, 0, 0, 1, —1jr. (90)
Analysis of the Markov chain In erms of the notation here, the probabilities in the main text
are
Corresponding to the matrix in Eq. (3), we define the stochastic Prob(AA AA) = (M")11 (91)
matrix
Prob(AB AB) = (M922 (92)
a2 0 0 2a(1 — a) 0 (1 — a?
0 be 0 a(1 — b) b(1 — a) (1 — a)(1 — b) Prob(BB BB) = (M")33 (93)
M = 0 0 d2 0 2d(1 — d) (1 — d)2 (75) Prob(AA A1= (M")14 (94)
0 0 0 ao 0 1— ao Prob(AB (95)
A) = (M")24
0 0 0 0 do 1— do
0 0 0 0 Prob(AB B) = (M"hs (96)
whose entries are the transition probabilities between the six Prob(BB B) = (97)
possible states (M. AB, BB, A, B. 0). Thus, M describes a Markov Prob(AA —0. 0) = (M")16 (98)
process with a single absorbing state (0). When this is iterated n
times, the probabilities of each of the six possible outcomes will be Prob(AB 0) = (M"126 (99)
the entries of the n-step transition probability matrix Al". Because Prob(BB 0) = (Mn)34. (100)
M is a triangular matrix, its eigenvalues are given by its diagonal
elements. These are just the probabilities ofremainingin each state We can define the limiting matrix
over a single iteration. For reference, we reproduce Eq. (4) A4(' ) = lim Mn = rig (101)
111-.DO
A= (l,a2 „bc.d2,a0. do) (76)
which has all six rows equal to [0. 0, 0. 0. 0, 1] and thus captures
and further note that 12, 13 and A4 are the probabilities that the fact that absorption in state 0 is guaranteed, ifn is large enough.
both individuals survive the iteration. Under the assumption that regardless of the starting state. Then we may write
neither surviving nor perishing of individuals is guaranteed over a 6
single iteration, which is to say 1 > a, b. c, d, ao. do > 0, xl = I is M" =m(-)i-E4,17. (102)
the largest eigenvalue and 1 > 12,13, 13, A6 > 0. i-2
From the standard theory of finite Markov chains (cf. section
2.12 in Ewens, 2004), if ri and fi are the corresponding right and Because 1 > Ai > 0 for i E (2, 3, 4, 5. 6). the eventual rate of
left eigenvectors of M, normalized so that decay toward AO') will be depend on which Ai is the leading non-
unit eigenvalue of M. This, in turn, will depend on the values of a,
6 b, c, d, ao and do. Ifn is very large, the sum in Eq. (102) will become
ErA=1, (77) dominated by a single term, namely the one involving the largest
i- non-unit eigenvalue.
for each i E (1. 2, 3, 4. 5, 6). then M" may be expressed in terms of For example, if12 = a2 is the largest eigenvalue and n is very
its spectral decomposition large.
Prob(AA M) = (M")11 x ay' (103)
mn=EA.frilj (78)
Prob(AA —* A) = 04'114 —
2a(1 — )a2"
(104)
a2 — ao
in which T denotes the transpose. With A defined as above, the a( — a)
2a21
Prob(AA 0) = (ien16 I a2" ao (105)
corresponding right and left eigenvectors of the matrix M are
= [1, 1. 1, 1, 1. lir (79) Prob(AB 0) = (M")26 as- 1 (106)
r2= [1, O. 0, 0, O. OIT (80) Prob(BB 0) = (Ain)3o rr 1. (107)
r3 = [0, 1. 0, 0, 0, Of (81) Then the effects of selection via the game reduce to
r4 = [0, O. 1, 0, 0, OIT (82) a(n) — c(n)*.: a(n) = Prob(AA —. AA) Prob(AA A)/2
2a(1 — a) b(1 — c) a — ao a2n (108)
rs — 0,1, 0. 01 (83) a2 — ao
[ — e 'ap —bc .
c(1 — b) 2d(1 — d) b(n)— d(n) O. (109)
ro — [ be 0, I. (di. (84)
— do d2 Our general results, Eqs. (23) and (24), are written to facilitate the
direct inference of such conclusions.
fl = o, O. 0, 0, O. 11T (85)
2a(1 — a) Derivation oldie replicator equation
f2 = [1, 0,0, ao _ 02 .- 0, 1 2a(
an I_—a2a) (86)
We assume a well-mixed population of infinite size. Well-
b(1 — c) c(1 — b) b(1 — c) c(1 — b)1T mixed means specifically that initial partnerships in the game are
f3= [0, 1,0, 1
be—ao ' be —do ' be—ao be —do ] formed at random in proportion to the current frequencies of A
87) and B. The game is the only cause of death in the population
EFTA00810757
54 J. Wakefey and M. Nowak/Theoretical Population Biology 125 (2019)38-55
and the only source of differences in fitness. Here we consider a Loners must receive half the weight of intact pain in this account-
continuous-time model. The replicator equation for the iterated ing. So. what remains of the total population is represented as
survival game can be developed as follows. Changes in the frequen-
cies (x and y) ofA and B are given by a pair of differential equations x2(Prob(AA AA) + Prob(AA A)/2)
+ 2x(1 — x)(Prob(AB —. AB) + Prob(AB A)/2
= —x2 [2Prob(AA 0) + Prob(AA A)]
+ Prob(AB B)/2)
— 2xy[Prob(AB 0) + Prob(AB B)] + xo (110)
+ (1 — x)2(Prob(BB -* BB) Prob(BB B)/2). (121)
= —y2[2Prob(BB —* 0) Prob(BB B)]
— 2xy[Prob(AB 0) + Prob(AB (111) By definition, this is equivalent to the average fitness of the popu-
A)] + yO
lation. Using Eqs. (19) through (22), it may be written
in which the factor of 2 inside the brackets in Eqs. (110) and (111)
comes from the fact that both individuals die in the transition to tip = x2a(n) + x(1 — x)13(n)+ x(1 — x)c(n)+ (1 — x)2d(n). (122)
state 0. Individuals perish in the game, which causes x and y to Note that is proportional to 4, in Eqs. (110) and (I11). Finally.
decrease. This is balanced by reproduction, by the positive terms accounting as in Eq.( 114) for the fact that only one member ofeach
xib and yO. As there are only two types, y = 1 - x. sox + y = 1 intact AB pair is A and El in Eq. (122) for the average fitness, the
and +j, = 0. Then using these to solve for ib and substituting into frequency of A after the game is
Eq. (110) gives
aC = (x2a(n) + x(1 — x)b(n))/Cb. (123)
=2x(1 — x)([Prob(AB 0) + Prob(AB A)
Then the change in the frequency of A over one generation, Ax =
— Prob(AA 0) — Prob(AA A)/2]x — x, is given by
+ [Prob(BB 0) + Prob(BB B)/2 Ax =x(1 — x)((a(n)— c(n)fx + [b(n)— d(n)1(1 — x))/ii.• (124)
— Prob(AB 0) — Prob(AB B)](1 — x)). (112) which is presented in the main text as Eq. (27).
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